Question

A liquid of mass m and specific heat s is at temperature $\theta$. Another liquid of mass 2 m and specific heat s/2 is at $3\theta$. If these two liquids are mixed, then calculate the resultant temperature of the mixture.

Answer 1

Let the resultant temperature be t
According to the principle of calorimetry,
$Heatlost=Heatgained$
$m\times S(-\theta +t)=2m\times \frac{S}{2}\times (-t+3\theta )$
$t-\theta =3\theta -t$
$2t=4\theta$

$t=2\theta$

$\therefore$ The resultant temperature is $2\theta$