The correct option is B 5 m/s
Given, force=5 N, mass =2 kg, displacement =5 m and initial velocity(u)=0 m/s as object was initially at rest.
Applying Work - Energy theorem,
Net work done = Change in Kinetic energy.
W=Force×Displacement=12m(v2−u2)
5×5=12m(v2−u2) as (u=0)
⇒25=12×2×(v2)
v=5 m/s
Hence option B is the correct answer.