Question

A man goes 10 m due east and then 24 m due north. find the distance from the starting point.

• A. $10m$
• B. $16m$
• C. $26m$
• D. $30m$

Answer 1

The correct option is C $26m$

Let the initial position of the man be O and his final position be B. Since the man goes 10 m due east and then 24 m due north. Therefore, $△AOB$ is a right triangle right-angled at A such that OA=10 m and AB=24 m.

By pythagoras theoram, we have

${OB}^2={OA}^2+{AB}^2$

$\Rightarrow$ ${OB}^2={10}^2+{24}^2=100+576=676$

$\Rightarrow$ $OB=\sqrt{676}=26m$

Hence, the man is at a distance of $26m$ from the starting point.