A man is standing on a weighing machine placed in a lift. When stationary his weight is recorded as 40 kg. If the lift is accelerated upwards with an acceleration of 2m/s2, then the weight recorded in the machine will be (g=10m/s)2
A
32 kg
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B
40 kg
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C
42 kg
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D
48 kg
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Solution
The correct option is D 48 kg When man is stationary his FBD ⇒N=mg ⇒m=Ng=40kg When lift accelerates, Pseudo force acts as lift is non-inertial frame. FBD in non-inertial frame
⇒N′=m(g+a) N′=40(g+a) Mass reading N′g=40(g+a)g=40(1210)=48kg