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Velocity Ratio

A man is stan...

Question

A man is standing on a weighting machine placed in a lift. When stationary, his weight is recorded as $40 k g$ . It the lift is accelerated upwards with an acceleration of ${2 m / s}^{2}$ , then the weight recorded in the machine will be $(g = 10 {m / s}^{2})$

A

32 k g

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B

40 k g

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C

42 k g

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D

48 k g

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Solution

The correct option is C $48 k g$
W(initial) $= m g = 40$
$\Rightarrow m = 4$ .
Weight $W^{^{'}}$ when lift accelerates up.
$= m (g + a)$
$= 4 (10 + 2) = 48$

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