1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# A man loses 20% of his money. After spending 25% of the remainder, he has Rs 480 left. How much money did he originally have?

Open in App
Solution

## Let the money that the man has be x.Money lost =20% of original money =20% of x=0.2×xMoney he has after losing = Original money − money lost =x−0.2x=0.8xAfter that, Money spent =25% of money after losing=0.25×0.8x=0.2xMoney Left = Money after losing − Money spent =0.8x−0.2x=0.6xBut Money left is given as Rs. 480.∴0.6x=480⇒x=4800.6∴x=800 so, he originally had Rs. 800. OR Since he loses 20% of the money, he is left with 80% of the money, which can be written as (80100)×x=0.8x Now, he spends 25% of this money. So after spending, he is left with 75% of that money. That would be (75100)×(0.8x)=0.6x We are given that 0.6x=480 On solving, we get x = Rs. 800

Suggest Corrections
128
Join BYJU'S Learning Program
Related Videos
Percentages and Why Percentages
MATHEMATICS
Watch in App
Explore more
Join BYJU'S Learning Program