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Question

A man loses 20% of his money. After spending 25% of the remainder, he has Rs 480 left. How much money did he originally have?

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Solution

Let the money that the man has be x.

Money lost =20% of original money =20% of x=0.2×x

Money he has after losing = Original money money lost

=x0.2x=0.8x

After that, Money spent =25% of money after losing

=0.25×0.8x

=0.2x

Money Left = Money after losing Money spent

=0.8x0.2x=0.6x

But Money left is given as Rs. 480.

0.6x=480

x=4800.6

x=800

so, he originally had Rs. 800.


OR

Since he loses 20% of the money, he is left with 80% of the money, which can be written as (80100)×x=0.8x
Now, he spends 25% of this money. So after spending, he is left with 75% of that money.
That would be (75100)×(0.8x)=0.6x
We are given that
0.6x=480
On solving, we get x = Rs. 800

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