Question

A man loses $12\frac{1}{2}$% of his money and after spending $70\%$ of the remainder, he was left with Rs. $210.$ The money that he had at the beginning is

• A. Rs. $810$
• B. Rs. $800$
• C. Rs. $790$
• D. Rs. $780$

Answer 1

The correct option is B Rs. $800$

Given that, a man loses $12\frac{1}{2}\%$ of his money and after spending $70\%$ of the remainder, he was left with $Rs.210.$

Let the money that he had at the beginning is $=x$.

Now, according the question,

$(x-12\frac{1}{2}\%ofx)-70\%of(x-12\frac{1}{2}\%ofx)=210$

$(x-\frac{x}{8})-\frac{70}{100}(x-\frac{x}{8})=210$

$\left(\frac{7x}{8}\right)-\left(\frac{49x}{80}\right)=210$

$\left(\frac{21x}{80}\right)=210$

$x=\frac{210\times 80}{21}$

$x=Rs.800$

Hence, this is the answer.