Question

A man's age is three times that of his son, and in twelve years he will be twice as old as his son would be. What are their present ages.

Answer 1

Let present age of the son = x years

$\therefore$ present age of the man = 3x years In 12 years :

Son's age will be = (x + 12) years

The man's age will be = (3x + 12) years

According to the statement :

$3x+12=2(x+12)\Rightarrow 3x+12=2x+24\Rightarrow 3x-2x=24-12\Rightarrow x=12\therefore 3x=3\times 12=36$

Hence, present age of the man = 36 years

Present age of the son = 12 years.