Question

A man slides down a light light rope whose breaking strength is $\eta$ times the weight of man ($\eta$<1) . The maximum acceleration of the man so that the rope just breaks is

• A. $g(1-\eta )$
• B. $g(1÷\eta )$
• C. g$\eta$
• D. $\frac{g}{\eta }$

Answer 1

The correct option is A $g(1-\eta )$

$T_{mac}=n\left(mg\right)$

$mg-T_{max}=ma$

$mg-nmg=ma$

$a=g(1-n)$

Option (a).