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Question

A man standing on a spring balance inside a stationary lift measures $60 kg$ . The weight of that person if the lift descends with a uniform downward acceleration of $1.8 {m/s}^{2}$ will be _____ $N$ .
$[g = 10 {m/s}^{2}]$

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Solution

From ground frame of reference,
$M g - N = M a$

$\Rightarrow N = M (g - a)$

$\Rightarrow N = 60 (10 - 1.8) = 492 N$

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