A man walks $1$ km towards East and then he turns to south and walks $5$ kms. Again he turns to East and walks $2$ kms after this he turned to North and walks $9$ kms. Now how far is he from the starting point?

3

kms

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4

kms

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5

kms

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7

kms

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Solution

The correct option is C $5$ kms
The man's positions are as shown in the figure.
The distance between his final and original position is $A E :$
$A E^{=} A L^{2} + L E^{2}$
$A E^{2} = (1 + 2)^{2} + (9 - 5)^{2}$
$A E^{2} = 3^{2} + 4^{2}$
$A E^{2} = 9 + 16 = 25$
$A E = 5$

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Q. A man walks 1 km towards East and then he turns to South and walks 5 km. Again he turns to East and walks 2 km, after this he turns to North and walks 9 km. Now, how far is he from his starting point?

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5

Km. Again he turns to East and walks

2

Km. After this, he turns to North and walks

9

Km. Now, how far is he from his starting point?

Q. A man walks 2 km towards North. Then he turns to East and walks 10 km. After this he turns to North and walks 3 km. Again he turns towards East and walks 2 km. How far is he from the starting point?

A man walks 1 km towards East, turns to South and walks 5 km. Again he turns to East and walks 2 km, after which he turns to North and walks 9 km. How far is he from his starting point?

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A man walks 1 km towards East and then he turns to south and walks 5 kms. Again he turns to East and walks 2 kms after this he turned to North and walks 9 kms. Now how far is he from the starting point?

The correct option is C 5 kmsThe man's positions are as shown in the figure.The distance between his final and original position is AE:AE=AL2+LE2AE2=(1+2)2+(9−5)2AE2=32+42AE2=9+16=25AE=5

A man walks $1$ km towards East and then he turns to south and walks $5$ kms. Again he turns to East and walks $2$ kms after this he turned to North and walks $9$ kms. Now how far is he from the starting point?

The correct option is C $5$ kms
The man's positions are as shown in the figure.
The distance between his final and original position is $A E :$
$A E^{=} A L^{2} + L E^{2}$
$A E^{2} = (1 + 2)^{2} + (9 - 5)^{2}$
$A E^{2} = 3^{2} + 4^{2}$
$A E^{2} = 9 + 16 = 25$
$A E = 5$