A man walks 1 km towards East and then he turns to South and walks 5 kms. Again he turns to East and walk 2 kms, after this he turns to North and walks 9 kms. Now how far is he from his starting point?

3 kms

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4 kms

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5 kms

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

7 kms

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 5 kms
The man starts from Aand moves to $B \to C \to D \to E$ (his final position).
Mans distance from $A = A E N o w {A E}^{2} = {A L}^{2} + {L E}^{2} = {(1 + 2)}^{2} + {(9 - 5)}^{2} = 9 + 16 = 25 ∴ A E = 5$

Suggest Corrections

Similar questions

Q. A man walks 1 km towards East and then he turns to South and walks 5 km. Again he turns to East and walks 2 km, after this he turns to North and walks 9 km. Now, how far is he from his starting point?

Q. A man walks

1

Km to East and then he turns to South and walks

5

Km. Again he turns to East and walks

2

Km. After this, he turns to North and walks

9

Km. Now, how far is he from his starting point?

Q. A man walks 2 km towards North. Then he turns to East and walks 10 km. After this he turns to North and walks 3 km. Again he turns towards East and walks 2 km. How far is he from the starting point?

A man walks 1 km towards East, turns to South and walks 5 km. Again he turns to East and walks 2 km, after which he turns to North and walks 9 km. How far is he from his starting point?

Join BYJU'S Learning Program

A man walks 1 km towards East and then he turns to South and walks 5 kms. Again he turns to East and walk 2 kms, after this he turns to North and walks 9 kms. Now how far is he from his starting point?

The correct option is C 5 kmsThe man starts from Aand moves to B→C→D→E(his final position). Mans distance from A=AENowAE2=AL2+LE2=(1+2)2+(9−5)2=9+16=25∴AE=5

The correct option is C 5 kms
The man starts from Aand moves to $B \to C \to D \to E$ (his final position).
Mans distance from $A = A E N o w {A E}^{2} = {A L}^{2} + {L E}^{2} = {(1 + 2)}^{2} + {(9 - 5)}^{2} = 9 + 16 = 25 ∴ A E = 5$