A man walks 1 km towards East and then he turns to South and walks 5 km. Again he turns to East and walks 2 km, after this he turns to North and walks 9 km. Now, how far is he from his starting point?

3 km

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4 km

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5 km

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

7 km

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 5 km

$C l e a r l y, D F = B C = 5 k m .$

$E F = (D E - D F) = (9 - 5) k m = 4 k m .$

$B F = C D = 2 k m$

$A F = A B + B F = A B + C D = (1 + 2) k m = 3 k m$

$∴ Man's distance from starting point A$

$= A E = \sqrt{A F^{2} + E F^{2}} = \sqrt{3^{2} + 4^{2}}$

$= \sqrt{25} = 5 k m$

Suggest Corrections

Similar questions

Q. A man walks 1 km towards East and then he turns to South and walks 5 kms. Again he turns to East and walk 2 kms, after this he turns to North and walks 9 kms. Now how far is he from his starting point?

Q. A man walks

1

Km to East and then he turns to South and walks

5

Km. Again he turns to East and walks

2

Km. After this, he turns to North and walks

9

Km. Now, how far is he from his starting point?

Q. A man walks 2 km towards North. Then he turns to East and walks 10 km. After this he turns to North and walks 3 km. Again he turns towards East and walks 2 km. How far is he from the starting point?

A man walks 1 km towards East, turns to South and walks 5 km. Again he turns to East and walks 2 km, after which he turns to North and walks 9 km. How far is he from his starting point?

Join BYJU'S Learning Program

A man walks 1 km towards East and then he turns to South and walks 5 km. Again he turns to East and walks 2 km, after this he turns to North and walks 9 km. Now, how far is he from his starting point?

The correct option is C 5 km Clearly, DF=BC=5 km. EF=(DE−DF)=(9−5) km=4 km. BF=CD=2 km AF=AB+BF=AB+CD=(1+2) km=3 km ∴Man's distance from starting point A =AE=√AF2+EF2=√32+42 =√25=5 km