A man walks $5 K m$ towards east, then takes a turn towards south and walk $12 K m$ . How far is he from starting point?

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Solution

According to Pythagoras theorem
${A C}^{2} = {A B}^{2} + {B C}^{2}$
${A C}^{2} = 12^{2} + 5^{2}$
${A C}^{2} = 169$
$∴ A C = 13 ㎞$

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A man walks 5 Km towards east, then takes a turn towards south and walk 12 Km. How far is he from starting point?

According to Pythagoras theoremAC2=AB2+BC2AC2=122+52AC2=169∴AC=13㎞

A man walks $5 K m$ towards east, then takes a turn towards south and walk $12 K m$ . How far is he from starting point?

According to Pythagoras theorem
${A C}^{2} = {A B}^{2} + {B C}^{2}$
${A C}^{2} = 12^{2} + 5^{2}$
${A C}^{2} = 169$
$∴ A C = 13 ㎞$