A man walks 8 km due North, then 5 km to East and 4 km to North. How far is he from the starting point?

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Solution

Let O and C be the initial and final positions of the man. In the figure, ΔODC is a right-angled triangle.

Applying Pythagoras theorem in ΔODC, we have:

Hence, the man is 13 km from the starting point.

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A man walks 8 km due North, then 5 km to East and 4 km to North. How far is he from the starting point?

Let O and C be the initial and final positions of the man. In the figure, ΔODC is a right-angled triangle. Applying Pythagoras theorem in ΔODC, we have: Hence, the man is 13 km from the starting point.

Let O and C be the initial and final positions of the man. In the figure, ΔODC is a right-angled triangle.

Applying Pythagoras theorem in ΔODC, we have:

Hence, the man is 13 km from the starting point.