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Standard VIII

Mathematics

Dilations

A man walks i...

Question

A man walks in $1$ km east. Now he turns south and walks $5$ km, again he turns east and walks $2$ km. At last, he turns north and walks $9$ km. Now in which direction and how far is he from the initial point?

4

km, North

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4

km, North-East

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5

km, East

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5

km, North-East

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Solution

The correct option is D $5$ km, North-East

In right triangle $A E F,$
$A F = \sqrt{A E^{2} + E F^{2}} = \sqrt{3^{2} + 4^{2}}$
$∴ A F = 5$ km, North-East

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A man walks in 1 km east. Now he turns south and walks 5 km, again he turns east and walks 2 km. At last, he turns north and walks 9 km. Now in which direction and how far is he from the initial point?

The correct option is D 5 km, North-East In right triangle AEF, AF=√AE2+EF2=√32+42 ∴AF=5 km, North-East

A man walks in $1$ km east. Now he turns south and walks $5$ km, again he turns east and walks $2$ km. At last, he turns north and walks $9$ km. Now in which direction and how far is he from the initial point?

The correct option is D $5$ km, North-East

In right triangle $A E F,$
$A F = \sqrt{A E^{2} + E F^{2}} = \sqrt{3^{2} + 4^{2}}$
$∴ A F = 5$ km, North-East