A marble tile measures 15 cm × 20 cm. How many tiles will be required to cover a wall of size 4 m × 6 m? Also, find the total cost of the tiles at the rate of Rs 2 per tile.

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Solution

Dimensions of the tile = 15 cm × 20 cm
Dimensions of the wall = 4 m × 6 m = 400 cm × 600 cm (Since, 1 m = 100 cm, so, 4 m = 400 cm and 6 m = 600 cm)
Area of the tile = 15 cm × 20 cm = 300 cm²
Area of the wall = 400 cm × 600 cm = 2,40,000 cm²

Number of tiles required to cover the wall = $\frac{A r e a o f w a l l}{A r e a o f o n e t i l e}$ = $\frac{240000}{300}$ = 800 tiles

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