A mass m is suspended by a rope from a rigid support at P as shown in the figure. Another rope is tied at the end Q which is pulled horizontally with a force F. If the rope PQ makes angle θ with the vertical, then tension in the string PQ is
A
Fsinθ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Fsinθ
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
Fcosθ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Fcosθ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is BFsinθ Let us consider all the forces acting at the point Q.
Taking components of T in vertical and horizontal direction, we get; Tx=Tsinθ and Ty=Tcosθ For horizontal equilibrium: Tsinθ=F⇒T=Fsinθ