Question

A mass $M$ is suspended by a rope from a rigid support at $P$ as shown in the figure. Another rope is tied at the end $Q$, and it is pulled horizontally with a force $F$. If the rope $PQ$ makes angle $\theta$ with the vertical then the tension in the string $PQ$ is:

• A. $F\sin \theta$
• B. $\frac{F}{\sin \theta }$
• C. $F\cos \theta$
• D. $\frac{F}{\cos \theta }$

Answer 1

The correct option is B $\frac{F}{\sin \theta }$

Let the tension in the string be $T$.

Horizontal component of tension is $Tsin\theta$ which balances $F$.

So, $T=\frac{F}{sin\theta }$