A match box measures 5 cm - 5-5 cm - 6-5 cm- What is the volume of 12 such boxes-A- 2135 cm 3B- 2045 cm 3C- 2245 cm 3D- 2145 cm 3

The correct option is D 2145 cm^3 Volume of one match box = (V)= length × breadth × height =(5×5.5×6.5)cm^3= 178.75 cm^3 ∴ Required volume = Volume of 12 matc ...

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Standard VI

Mathematics

Volume of Rectangular Box Using Unit Cubes

A match box m...

Question

A match box measures 5 cm $\times$ 5.5 cm $\times$ 6.5 cm. What is the volume of 12 such boxes?

$2135 c m^{3}$

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$2045 c m^{3}$

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$2245 c m^{3}$

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$2145 c m^{3}$

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Solution

The correct option is D
$2145 c m^{3}$

Volume of one match box = $(V) = l e n g t h \times b r e a d t h \times h e i g h t$
$= (5 \times 5.5 \times 6.5) c m^{3} = 178.75 c m^{3}$
$∴$ Required volume = Volume of 12 match boxes
$= 12 \times 178.75 c m^{3} = 2145 c m^{3}$

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A match box measures 5 cm × 5.5 cm × 6.5 cm. What is the volume of 12 such boxes?

The correct option is D 2145cm3 Volume of one match box = (V)=length×breadth×height =(5×5.5×6.5)cm3=178.75cm3 ∴ Required volume = Volume of 12 match boxes =12×178.75cm3=2145cm3

A match box measures 5 cm $\times$ 5.5 cm $\times$ 6.5 cm. What is the volume of 12 such boxes?

The correct option is D
$2145 c m^{3}$

Volume of one match box = $(V) = l e n g t h \times b r e a d t h \times h e i g h t$
$= (5 \times 5.5 \times 6.5) c m^{3} = 178.75 c m^{3}$
$∴$ Required volume = Volume of 12 match boxes
$= 12 \times 178.75 c m^{3} = 2145 c m^{3}$