Question

A metallic hemispherical bowl is $0.25cm$ thick. The inside radius of the bowl is $5cm$. Find the volume of steel used in making the bowl.

Answer 1

Volume of hemisphere $=\frac{2}{3}\pi (R^3-r^3)$

where

$R=$Outer radius

$r=$Inner radius

$V=\frac{2}{3}\pi ({4.5}^3-4^3)$

$=\frac{2}{3}\times \frac{22}{7}\times (91.125-64)$

$=56.83c{m}^3$

Hence the volume of steel used to make hemispherical bowl is $56.83c{m}^3$