Question

A metallic wire has a resistance of $3.0\Omega$ at $0^{o}C$ and $4.8\Omega$ at ${150}^{o}C$. Find the temperature coefficient of resistance of its material.

Answer 1

Given, $R_0=3.0\Omega ,R_t=4.8\Omega$ and $t={150}^{o}C$
Let, Temperature coefficient of resistance be $\left(\alpha \right)$
We know that,
$R_t=R_0(\alpha +\alpha △t)$
$4.8=3(1+\alpha \times 150)$
$\therefore \alpha =\frac{4.8-3}{3\times 150}=0.004per{}^{o}C$