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Standard X

Physics

Ohm's Law

A meter bridg...

Question

A meter bridge is set-up as shown, to determine an unknown resistance X using a standard
10 ohm resistor. The galvanometer shows null point when tapping key is at 52 cm mark. The end corrections are 1 cm and 2 cm respectively for the ends A and B. The determined value of X is

10.6 ohm

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10.8 ohm

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10.2 ohm

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11.1 ohm

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Solution

The correct option is A 10.6 ohm
$\frac{X}{53} = \frac{10}{50} \Rightarrow X = 10.6 Ω$

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A meter bridge is set-up as shown, to determine an unknown resistance X using a standard 10 ohm resistor. The galvanometer shows null point when tapping key is at 52 cm mark. The end corrections are 1 cm and 2 cm respectively for the ends A and B. The determined value of X is

The correct option is A 10.6 ohmX53=1050⇒X=10.6 Ω

A meter bridge is set-up as shown, to determine an unknown resistance X using a standard
10 ohm resistor. The galvanometer shows null point when tapping key is at 52 cm mark. The end corrections are 1 cm and 2 cm respectively for the ends A and B. The determined value of X is

The correct option is A 10.6 ohm
$\frac{X}{53} = \frac{10}{50} \Rightarrow X = 10.6 Ω$