Question

A mixture if $CO$ and ${CO}_2$ is found to have a density of $1.5gm/L$ of ${30}^{o}C$ and of 730 four. What is the composition of the mixture?

Answer 1

Let us consider $PV=nRT$ implies that

$PV=\frac{w}{M}RT$

implies that M

$PM=\frac{w}{v}RT$

Since $\frac{W}{V}$=density

implies that

$PM=dRT$

$M=\frac{dRT}{M}-\left(1\right)$

given that

$d=1.50g{l}^{-1}$

$p=760$

$T={30}^{0}c=303K$

molar mass of $CO=28.01gmo{l}^{-1}$

molar mass $CO=44.01gmo{l}^{-1}$

Let us the composition of $CObex\%$

$C{O}_2=\left(1-x\right)\%$

Hence the average molar mass $28.01\times x+44.01\times \left(1-x\right)$

$=44.01-0.16x-\left(2\right)$

Substitute equation 2 in 1 we have

$44.01-0.16x=\frac{1.50\times 62.36\times 3.3}{760}$

implies that

$-0.16x=37.3-44.01$

implies that

$-0.16x=-0.71$

implies that

$x=41.94\%$