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Nucleophilic Substitution Reaction

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Question

A mixture of CaCl^2 and NaCl weighing 4.44g is treated with sodium carbonate solution to precipitate all the calcium ions as calcium carbonate . The calcium carbonate so obtainable is heated strongly to get 0.56g of CaO . The percentage of NaCl in mixture is

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Solution

Weight of CaO=0.56g

0.56g of CaO contains 0.40g of calcium

Mol.weight of CaCl2=40+71=111

Therefore 0.4 g of calcium present in (0.40111)/40=1.11g of CaCl2

Amount of NaCl present in mixture =4.44-1.11=3.33g

Therefore percentage of NaCl =(3.33100)/4.44=75

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