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Question

A mixture of monoatomic gas (n1 moles) and diatomic gas (n2 moles) has CPCV equal to 117. Then

A
n1=3n2
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B
n2=3n1
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C
n1=n2
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D
5n1=2n2
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Solution

The correct option is A n1=3n2
If n1 moles of a gas of ratio of specific heat γ1 ​ is mixed with n2 ​ moles of another gas of ratio of specific heat γ2 , then the ratio of specific heats of the mixture γ is given by,

n1+n2γ1=n1γ11+n2γ21

Given, γ=117

For monatomic gas, γ1=53

For diatomic gas, γ2=75

n1+n21171=n1531+n2751

7n1+7n24=3n12+5n22

7n1+7n2=6n1+10n2

n1=3n2

Hence, option (a) is the correct answer.

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