A moving coil galvanometer of 50Ω resistance gives full deflection when a current of 0.5mA. To convert this galvanometer into a voltmeter of 10V range, the resistance to be connected in series with the galvanometer is
A
18005Ω
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B
20050Ω
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C
19050Ω
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D
17050Ω
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Solution
The correct option is C19050Ω Given, G=50Ω;Ig=0.5mA;V=10V
V=Ig(G+R)
10=0.5×10−3(50+R)
2×104=50+R
R=20000−50
R=19050Ω
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Hence, (C) is the correct answer.