Question

A neutron is confined to a nucleus of size ${10}^{-14}m$.The minimum momentum of the electron may be

• A. $6.6\times {10}^{-20}Kg.m/s$
• B. $3.3\times {10}^{-20}Kg.m/s$
• C. $3.3\times {10}^{-48}Kg.m/s$
• D. $6.6\times {10}^{-48}Kg.m/s$

Answer 1

Answer: (B)

$3.3\times {10}^{-20}Kg.m/s$

Since,$\Delta x\Delta p=h$
$\therefore 2\times {10}^{-14}\times \Delta p=6.6\times {10}^{-34}$
$\Rightarrow \Delta p=\frac{6.6\times {10}^{-34}}{2\times {10}^{-14}}$
$\Rightarrow \Delta p=3.3\times {10}^{-20}Kg.m/s$