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Question

A neutron moving with velocity u collides with a stationary αparticle The velocity of the neutron after collision is

A
35
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B
35
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C
25
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D
25
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Solution

The correct option is A 35
Mass of alpha particle is 4 times to neutron
according to the condition alpha paticle is at rest so its velocity is zero
now the final velocity of neutron is calculated from this formula
U=(m1m2÷m1+m2)U1
by putting,
U=(14÷1+4)
=3U/5
Negative sign shows reverse direction of neutro.
Hence,
option (A) is correct answer.


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