A new unit of length is chosen such that the speed of light in vacuum is unity. What is the distance between the Sun and the Earth in terms of the new unit if light takes $8 min$ ⁡⁡⁡and $20 s$ to cover this distance?

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Solution

Given: According to the problem, speed of light in
vacuum, $c = 1$ new unit of length $s^{- 1}$
Time taken by light to cover distance between sun and earth
$t = 8 min 20 s = 500 s$

$∴$ Distance between sun and earth (in terms of new unit)
$= c \times t = 1$ (new unit of length $\times 500 s$ )

$= 500$ new units of length

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A new unit of length is chosen such that the speed of light in vacuum is unity. What is the distance between the Sun and the Earth in terms of the new unit if light takes 8 min ⁡⁡⁡and 20 s to cover this distance?

Given: According to the problem, speed of light in vacuum, c=1 new unit of length s−1 Time taken by light to cover distance between sun and earth t=8 min 20 s=500 s ∴ Distance between sun and earth (in terms of new unit) =c×t=1 (new unit of length ×500 s) =500 new units of length

A new unit of length is chosen such that the speed of light in vacuum is unity. What is the distance between the Sun and the Earth in terms of the new unit if light takes $8 min$ ⁡⁡⁡and $20 s$ to cover this distance?