A nucleus with mass number 220 initially at rest emits an $α - p a r t i c l e$ . If the Q value of the reaction is 4 MeV. Calculate the kinetic energy of the $α - p a r t i c l e$

3.9 MeV

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

5.4 MeV

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5.6 MeV

No worries! We‘ve got your back. Try BYJU‘S free classes today!

6.5 MeV

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 3.9 MeV

Q-value of the reaction is 4MeV i.e. $k_{1} + k_{2} = 4 M e V$ ........... (i)
By conservation of linear momentum $p_{1} = p_{2} \Rightarrow \sqrt{2 (216) k_{1}} = \sqrt{2 (4) k_{2}} \Rightarrow k_{2} = 54 k_{1}$ ............. (ii)
On solving equation (i) and (ii) we get $k_{2} = 3.9 M e V$

Suggest Corrections

Similar questions

A nucleus with mass number 220 initially at rest emits an $α$ -particle. If the Q value of the reaction is 5.5 MeV, then the kinetic energy of the $α$ -particle is

Q. A nucleus with mass number 220 initially at rest emits an

α

- particle. If Q value of reaction is 5 .5b MeV. Calculate the kinetic energy of the

α

particle

Q. A nucleus with mass number 220 initially at rest emits an

α

-particle. If the Q value of the reaction is 5.5 MeV. Calculate the kinetic energy of the

α

-particle

Q. A nucleus of mass number 220 initially at rest emits an alpha particle. If the

Q

value of the reaction is

5.5 M e V

, then the kinetic energy of the alpha particle is

Q. A nucleus with mass number

220

initially at rest emits an

α

-particle. lf the

Q

value of the reaction is

5.5

M e V

, calculate the kinetic energy of the

α

-particle.

Join BYJU'S Learning Program

A nucleus with mass number 220 initially at rest emits an α−particle. If the Q value of the reaction is 4 MeV. Calculate the kinetic energy of the α−particle

The correct option is A 3.9 MeV Q-value of the reaction is 4MeV i.e. k1+k2=4MeV ........... (i) By conservation of linear momentum p1=p2⇒√2(216)k1=√2(4)k2⇒k2=54k1 ............. (ii) On solving equation (i) and (ii) we get k2=3.9 MeV

A nucleus with mass number 220 initially at rest emits an $α - p a r t i c l e$ . If the Q value of the reaction is 4 MeV. Calculate the kinetic energy of the $α - p a r t i c l e$