A number die is thrown. Probability that a prime number will appear is............

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Solution

Given a die is thrown
$∴$ The sample space S $= {1, 2, 3, 4, 5, 6}$
Let $E$ be the event a prime number will appear
$∴ E = {2, 3, 5}$
Probability of getting prime number $= \frac{n (E)}{n (S)} = \frac{3}{6} = \frac{1}{2}$

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A number die is thrown. Probability that a prime number will appear is............

Given a die is thrown∴ The sample space S={1,2,3,4,5,6}Let E be the event a prime number will appear∴E={2,3,5}Probability of getting prime number =n(E)n(S)=36=12

Given a die is thrown
$∴$ The sample space S $= {1, 2, 3, 4, 5, 6}$
Let $E$ be the event a prime number will appear
$∴ E = {2, 3, 5}$
Probability of getting prime number $= \frac{n (E)}{n (S)} = \frac{3}{6} = \frac{1}{2}$