Question

A one kilowatt motor pumps out water from a $\text{10 m}$ deep well. Calculate the quantity of water pumped out per second.(Take $g=10\text{m}/{\text{s}}^2$)

• A. $\text{10 kg}$
• B. $\text{8.96 kg}$
• C. $\text{14.3 kg}$
• D. $\text{9.8 kg}$

Answer 1

The correct option is A $\text{10 kg}$

Given
Power $={\text{1 kilowatt =10}}^3\text{watt}$
$S=\text{10 m}$, time $=1\text{s}$, $g=10\text{m}/{\text{s}}^2$, Required mass of water $=m\text{kg}$

$\because$ Power$=\frac{\text{work done}}{t}$

$\Rightarrow$ Power$=\frac{mgS}{t}$
putting values (from given data)

${10}^3=\frac{m\times 10\times 10}{1}$
$\Rightarrow$ Required mass $=10\text{kg}$

hence option A is the correct answer