Question

A parallel plate air capacitor is charged to a potential difference of V volt. After disconnecting the charging battery, the distance between the plates of the capacitor is increased using an insulating handle. As a result, the potential difference between the plates

• A. Decreases
• B. Does not change
• C. Becomes zero
• D. Increases

Answer 1

The correct option is D

Increases

$C=\frac{{ϵ}_{0}A}{d};Q=CV$
If d increases, C decreases.
For a given charge Q, $C\alpha \frac{1}{V}$
As C decreases, V increases