A particle executes harmonic motion with an angular velocity and maximum acceleration of 3.5 rad/sec and 7.5 m/ $s^{2}$ respectively. The amplitude of oscillation is

[AIIMS 1999; Pb. PET 1999]

0.28 m

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0.36 m

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0.53 m

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0.61 m

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Solution

The correct option is D
0.61 m

$A_{m a x} = a ω^{2} \Rightarrow a = \frac{A_{m a x}}{ω^{2}} = \frac{7.5}{(3.5)^{2}} = 0.61 m$

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A particle executes harmonic motion with an angular velocity and maximum acceleration of 3.5 rad/sec and 7.5 m/s2 respectively. The amplitude of oscillation is [AIIMS 1999; Pb. PET 1999]

The correct option is D 0.61 m Amax=aω2⇒a=Amaxω2=7.5(3.5)2=0.61m

A particle executes harmonic motion with an angular velocity and maximum acceleration of 3.5 rad/sec and 7.5 m/ $s^{2}$ respectively. The amplitude of oscillation is

[AIIMS 1999; Pb. PET 1999]

The correct option is D
0.61 m

$A_{m a x} = a ω^{2} \Rightarrow a = \frac{A_{m a x}}{ω^{2}} = \frac{7.5}{(3.5)^{2}} = 0.61 m$