A particle executing SHM has amplitude of 4 cm., and its acceleration at a distance of 1 cm from the mean position is 3 cms−2. Its velocity be when it is at a distance of 2 cm from its mean position is
A
2cm/s
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B
3cm/s
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C
4cm/s
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D
6cm/s
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Solution
The correct option is D6cm/s a=−ω2x ω2=3;ω=√3radsec v=ω√A2−x2 =√3×√16−4 =√3×√12=6cm/s