Question

A particle is moving on a circular path of radius with uniform velocity v. The change in velocity when the particle moves from P to Q is ($\angle$POQ = 40${}^O$).

• A. 2v cos 40${}^{\circ }$
• B. 2v sin 40${}^{\circ }$
• C. 2v sin 20${}^{\circ }$
• D. 2v cos 20${}^{\circ }$

Answer 1

The correct option is C 2v sin 20${}^{\circ }$

It is clearly visible that, charge in velociy is = 2v sin $\left(\frac{\theta }{2}\right)$ = 2v sin 20$\circ$