Question

A particle moves from position $3\hat{i}+2\hat{j}-6\hat{k}$ to $14\hat{i}+13\hat{j}+9\hat{k}$ due to a uniform force of $(4\hat{i}+\hat{j}+3\hat{k})$N. If the displacement in m then work done will be

• A. 100 J
• B. 200 J
• C. 300 J
• D. 250 J

Answer 1

The correct option is A 100 J

Displacement of particle $\overrightarrow{S}=14\hat{i}+13\hat{j}+9\hat{k}-(3\hat{i}+2\hat{j}-6\hat{k})=11\hat{i}+11\hat{j}+15\hat{k}$

Force $\overrightarrow{F}=4\hat{i}+\hat{j}+3\hat{k}$

Work done $W=\overrightarrow{F}.\overrightarrow{S}=44+11+45=100J$