A particle moving with a uniform acceleration travels 24 m and 64 m in the first two consecutive intervals of 4 sec each. Its initial velocity is
Distance travelled in 4 sec
24=4u+12a×16 ...(i)
Distance travelled in total 8 sec.
88=8u+12a×64 ...(ii)
After solving (i)and (ii),we get u=1 m/s.