Question

A particle starts its motion from rest under the action of a constant force. If the distance covered in first 10 seconds is $S_1$ and that covered in the first 20 seconds is $S_2$ then:

• A. $S_2$ = $S_1$
• B. $S_2$ = $2S_1$
• C. $S_2$ = $3S_1$
• D. $S_2$ = $4S_1$

Answer 1

The correct option is D $S_2$ = $4S_1$

$S_1=\frac{1}{2}a(10{)}^2$

$S_2=\frac{1}{2}a(20{)}^2$

$\frac{S_1}{S_2}=\frac{100}{400}$

$S_2=4S_1$