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Question

A pendulum bob of mass 30mg carrying a charge of 2.0×108 is at rest in a uniform horizontal electric field of 20000N/C. The tension in the thread of the pendulum is (g=10m/s2):


A
5×104N
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B
4×104N
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C
3×104N
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D
2×104N
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Solution

The correct option is C 5×104N
Horizontal force acting on Charge=qE=2×108×20000
FH=4×104N

Vertical force acting on charge=mg=30×106×10=3×104N


Tension will be equal to resultant of electrostatic force and force due to gravity,

Fres=qE2+mg2=5×104N


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