A person measures the time period of a simple pendulum inside a stationary lift and finds it to be T. If the lift starts accelerating upwards with an acceleration of g/3, the time period of the pendulum will be

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
T = $2 π \sqrt{\frac{l}{g}} .$ When the lift accelerates upwards with an acceleration of ,
the effective acceleration is g' = $g + \frac{g}{3} = 4 \frac{g}{3}$
Therefore, the new time period is
$T^{'} = 2 π \sqrt{\frac{l}{g^{'}}} T h u s \frac{T^{'}}{T} = \sqrt{\frac{g}{g^{'}}} = \sqrt{\frac{g}{4 g / 3}} = \frac{\sqrt{3}}{2} o r T^{'} = \frac{\sqrt{3}}{2} T .$
Hence the correct choice is (b).

Suggest Corrections

Similar questions

A person measures the time period of a simple pendulum inside a stationary lift and finds it to be T . If the lift starts accelerating upwards with an acceleration g/3, the time period of pendulum will become

Time period of a simple pendulum measured inside a stationary lift is T. If the lift starts moving upwards with an acceleration of $\frac{g}{3}$ , what will be its time period:

Q. The period of a simple pendulum measured by inside a stationary lift 'T' . If the lift starts moving upward with a acceleration g/3 . What will be the time period?

The period of simple pendulum inside a stationary lift is T. The lift accelerates upward with an acceleration of g/3.The time period of simple pendulum will be

A man measures the period of a simple pendulum inside a stationary lift and finds it to be T sec. If the lift accelerates upwards with an acceleration g/4, then the period of the pendulum will be

Join BYJU'S Learning Program

A person measures the time period of a simple pendulum inside a stationary lift and finds it to be T. If the lift starts accelerating upwards with an acceleration of g/3, the time period of the pendulum will be

The correct option is B T = 2π√lg. When the lift accelerates upwards with an acceleration of , the effective acceleration is g' = g+g3=4g3 Therefore, the new time period is T′=2π√lg′Thus T′T=√gg′=√g4g/3=√32 or T′=√32T. Hence the correct choice is (b).