A person of mass 40kg is inside a lift of mass 960kg and presses the button on the control panel. The lift starts moving upwards with an acceleration 2m/s2. If g=10m/s2, the tension in the supporting cable is
A
8600N
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B
12000N
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C
11000N
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D
2000N
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Solution
The correct option is B12000N Let mass of lift be M=960kg mass of man is m=40kg acceleration of lift is a=2m/s2 vertically upwards. From the frame of reference of lift asystem=0 for system of (man+lift)
⇒In the FBD of (man+lift) system from lift frame, a pseudo force will be applied in vertically downward direction i.e opposite to acceleration of lift. Fpseudo=(M+m)a
From FBD for equilibrium of system i.e asystem=0 : ⇒T=(M+m)a+(M+m)g T=(M+m)(a+g) ∴T=(960+40)×(2+10)=12000N