Question

A piece of ice is floating in water. The fraction of volume of the piece of ice outside the water is $[{\rho }_{ice}-900kg/m^{3}and{\rho }_{water}=1000kg/m^3]$

• A. 0.21
• B. 0.01
• C. 0.1
• D. 0.9

Answer 1

The correct option is C 0.1

Let V be the total volume of ice piece and V' is the volume of ice piece which is outside the water, then $(V-V^{\prime }){\rho }_{water}g=V{\rho }_{ice}\times g\Rightarrow (V-V^{\prime })1000=V\times 900or{V}^{\prime }=\frac{V}{10}=0.1V.$ So, fraction of ice piece outside the water is, $f=\frac{V^{\prime }}{V}=0.1$ .