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Question

A piece of resistance wire has resistance of 4Ω . Its diameter is doubled. Now its resistance will be :

A
8Ω
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B
2Ω
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C
4Ω
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D
1Ω
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Solution

The correct option is D 1Ω
Resistance of a piece of wire = 4

4Ω=pLA

Given diameter of wire is doubled.

Area A =πd24

Now A1=π(2d)24=4A

New resistance R1=pLA1=pL4A

=14×4=1Ω

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