Question

A piece of wire $\frac{7}{8}m$ long broke into two pieces. One piece was $\frac{1}{4}m$ long. How long is the other piece $?$

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Solution

Finding the length of the wire:The total length of the wire$=\frac{7}{8}m$Length of one piece of wire$=\frac{1}{4}m$Length of another piece of wire$=$total length of the wire $-$length of one piece of wire $=\left(\frac{7}{8}-\frac{1}{4}\right)m\phantom{\rule{0ex}{0ex}}=\left(\frac{7×1-1×2}{8}\right)m\phantom{\rule{0ex}{0ex}}=\left(\frac{7-2}{8}\right)m\phantom{\rule{0ex}{0ex}}=\frac{5}{8}m$$\therefore$Hence, length of the other piece of wire is $\frac{5}{8}m$.

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