wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A planar closed kinematic chain is formed with a rigid link PQ = 2.0 m, QR =3.0 m, RS =2.5 m and SP =2.7 m with all revolute joints. The link to be fixed to obtain rocker (rocker-rocker) mechanism is

A
PQ
No worries! Weā€˜ve got your back. Try BYJUā€˜S free classes today!
B
QR
No worries! Weā€˜ve got your back. Try BYJUā€˜S free classes today!
C
RS
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
SP
No worries! Weā€˜ve got your back. Try BYJUā€˜S free classes today!
Open in App
Solution

The correct option is C RS
PQ = 2.0 m, QR = 3.0 m, RS = 2.5 m, SP = 2.7 m

(i) If shortest line PQ = 2.0 m is fixed, then we will get double crank

(ii) If link adjacent to shortest is fixed, then we will get crank-rocker mechanism

(iii) If we fix the coupler 'RS', we will get double rocker mechanism

Point to Remember
This problem is based on Grashoff's law, for continuous relative motion.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Simple Pendulum
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon