A planar closed kinematic chain is formed with a rigid link PQ = 2.0 m, QR =3.0 m, RS =2.5 m and SP =2.7 m with all revolute joints. The link to be fixed to obtain rocker (rocker-rocker) mechanism is
A
PQ
No worries! Weāve got your back. Try BYJUāS free classes today!
B
QR
No worries! Weāve got your back. Try BYJUāS free classes today!
C
RS
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
SP
No worries! Weāve got your back. Try BYJUāS free classes today!
Open in App
Solution
The correct option is C RS PQ = 2.0 m, QR = 3.0 m, RS = 2.5 m, SP = 2.7 m
(i) If shortest line PQ = 2.0 m is fixed, then we will get double crank
(ii) If link adjacent to shortest is fixed, then we will get crank-rocker mechanism
(iii) If we fix the coupler 'RS', we will get double rocker mechanism
Point to Remember
This problem is based on Grashoff's law, for continuous relative motion.