A point charge of $2 C$ experiences constant force of $1000 N$ when moved between two points separated by a distance of $2 c m$ in a uniform electric field. The potential difference between the two points is

12 V

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8 V

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10 V

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16 V

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5 V

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Solution

The correct option is B 10 V
Given
q=2C, F=100 N and $d = 2 \times 10^{- 2} m$
electric field $E = \frac{F}{q}$
$= \frac{1000}{2} = 500 N / c$
the potential difference
$V = E \times d$
$= 500 \times 2 \times 10^{- 2}$
$= 10^{3} \times 10^{- 2}$
$= 10 V$

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A point charge of 2 C experiences constant force of 1000 N when moved between two points separated by a distance of 2 cm in a uniform electric field. The potential difference between the two points is

The correct option is B 10 VGivenq=2C, F=100 N and d=2×10−2melectric field E=Fq=10002=500N/cthe potential differenceV=E×d=500×2×10−2=103×10−2=10V

A point charge of $2 C$ experiences constant force of $1000 N$ when moved between two points separated by a distance of $2 c m$ in a uniform electric field. The potential difference between the two points is

The correct option is B 10 V
Given
q=2C, F=100 N and $d = 2 \times 10^{- 2} m$
electric field $E = \frac{F}{q}$
$= \frac{1000}{2} = 500 N / c$
the potential difference
$V = E \times d$
$= 500 \times 2 \times 10^{- 2}$
$= 10^{3} \times 10^{- 2}$
$= 10 V$