Question

A positive point change $q$ is placed at a distance $2R$ from the surface of a metallic shell of radius $R$. The electric field at centre of shell due to induced charge has magnitude

• A. $Zero$
• B. $\frac{1}{4\pi {\epsilon }_0}\frac{q}{9R^2}$
• C. $\frac{1}{4\pi {\epsilon }_0}\frac{q}{4R^2}$
• D. $\frac{1}{4\pi {\epsilon }_0}\frac{q}{R^2}$

Answer 1

The correct option is A $Zero$

A positive point charge $=q$

distance $=2R$

shell of radius $=R$

The electric field at centre of shell due to induced charge $=0$ because, equipotential surface has zero electric field.