Question

A potential clifference of $220V$ is applied across a resistance of $440$$\Omega$ in an electrical appliance. Calculate the current drawn and the heat energy produced in $20seconds$.

• A. $2400J$
• B. $2300J$
• C. $2200J$
• D. $2500J$

Answer 1

Answer: (C)

$2200J$

Given:$V=220$v,$R=440\Omega$, $t=20$s

Current flowing through the circuit$=I=\frac{V}{R}=\frac{220}{440}=0.5$A

Heat energy is given by

$W=VIt=220\times 0.5\times 20=2200$J

$\therefore$ current flowing through circuit is $0.5$A and work done is $2200$J